Question

A cat pushes on a .25kg mouse toy for 3.0 seconds, resulting in a velocity of 18 m/s. The force of the cat was how many N?

Answer 1

`"1.5 N"`

Explanation:

Acceleration of toy

`"a" = ("v – u")/"t" = "18 m/s – 0 m/s"/"3.0 s" = "6 m/s"^2`

From Newton’s second law

`"F = ma"`

`"F = 0.25 kg × 6 m/s"^2 = "1.5 N"`