Question

A catcher catches a baseball that is traveling 126km/h. If the ball stops within 0.230s, what is its acceleration?

Answer 1

`"-152.17 m/s²"`

Explanation:

`126 " km/h" = (126/3.6) " m/s" = 35 " m/s"`
`v = v_0 + a*t`
`"So here we have"`
`0 = 35 + a*0.230`
`=> a = -35/0.230 = -152.17 m/s^2`

`v_0 = " initial velocity in m/s"`
`v = " velocity in m/s"`
`a = " acceleration in m/s²"`
`t = " time in seconds (s)"`