A charge of #1 C# is at #(-2,7,1)# and a charge of #2 C# is at #(0,-4 ,4) #. If both coordinates are in meters, what is the force between the charges?

1 Answer

#1.3433\times 10^8\ N#

Explanation:

The distance #d# between two points #(-2, 7, 1)# & #(0, -4, 4)# is given by distance formula

#d=\sqrt{(-2-0)^2+(7-(-4))^2+(1-4)^2}=\sqrt134#

Now, the electrostatic force #F# between the point charges #Q_1=1C# & #Q_2=2 C# at a distance #d=\sqrt134#

#F=\frac{1}{4\pi\epsilon_0}\frac{Q_1Q_2}{d^2}#

#=(9\times 10^9)\frac{1\cdot 2}{(\sqrt134)^2}#

#=1.3433\times 10^8\ N#