A charge of #1 C# is at #(-2,7,1)# and a charge of #2 C# is at #(8,-1,4) #. If both coordinates are in meters, what is the force between the charges?

1 Answer
Jan 31, 2018

Answer:

#F=1.04times10^8 N#

Explanation:

Charge #1C# placed at #(-2,7,1)#
Charge #2C# placed at #(8,-1,4)#

Distance between the charges
#r=sqrt((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2#
#r=sqrt((8-(-2))^2+((-1)-7)^2+(4-1)^2#
#r=sqrt((8+2)^2+(-1-7)^2+(4-1)^2)#
#r=sqrt(10^2+(-8)^2+(3)^2)#
#r=sqrt(100+64+9)=sqrt(173)#

Force between charges
#F=(kq_1q_2)/r^2#
where #k=9times10^9 N-m^2/C^2#

#F=(9times10^9times1times2)/(sqrt173)^2#
#F=(18times10^9)/173=0.104times10^9#
#F=1.04times10^8 N#