A charge of 1 C is at (-7, 1 ) and a charge of -3 C is at (3, 5 ) . If both coordinates are in meters, what is the force between the charges?

Feb 27, 2016

$2.33 \times {10}^{5}$

Explanation:

first we have to measure the distance,

$r = \sqrt{{\left(3 + 7\right)}^{2} + {\left(5 - 1\right)}^{2}}$
$= \sqrt{100 + 16}$
$= \sqrt{116}$

we know,

$F = \frac{1}{4 \pi \epsilon} \frac{{q}_{1} {q}_{2}}{r} ^ 2$

$= 9 \times {10}^{9} \times \frac{1 \times - 3}{116}$

$= 2.33 \times {10}^{5}$