A charge of #12 C# passes through a circuit every #8 s#. If the circuit can generate #8 W# of power, what is the circuit's resistance?

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Answer 1 · 2016-05-02T11:46:29

#R=3,56 " "Ohm#

#"electric current :" I=(Delta Q)/(Delta t)#

#I=12/8=1,5 A#

#"Power="I^2*R" #

#R=("Power")/I^2#

#R=8/(1,5)^2#

#R=8/(2,25)#

#R=3,56 " "Ohm#