A charge of #15 C# passes through a circuit every #12 s#. If the circuit can generate #14 W# of power, what is the circuit's resistance?

1 Answer
Mar 20, 2016

#R=8,96 " Ohm"#

Explanation:

#"first ; we must find the electric current:"#
#"I=Electric current"#
#Delta Q":charge"#
#Delta "t:time"#
#I=(Delta Q)/(Delta t)#
#I=15/12=5/4" A"#
#P:Power#
#"R:Resistance of circuit"#
#"The Electric power is given as formula:"#
#P=I^2*R#
#14=(5/4)^2*R#
#14=25/16*R#
#R=(14*16)/25#
#R=8,96 " Ohm"#