A charge of #18 C# passes through a circuit every #12 s#. If the circuit can generate #12 W# of power, what is the circuit's resistance?

Question

1211 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-23T12:41:25

The resistance is #=5.33Omega#

Apply the equation

#"Charge"(C)"# #= "Current(A)"xx"time (t)"#

The charge is #Q=18C#

The time is #t=12s#

The current is #I=18/12=1.5A#

Ohm's Law states that

#U=RI#

The power is

#P=UI=RI^2#

The power is #P=12W#

The resistance is

#R=P/(I^2)=12/(1.5)^2=5.33Omega#