Question

A charge of `18 C` passes through a circuit every `12 s`. If the circuit can generate `1 W` of power, what is the circuit's resistance?

Answer 1

`4/9 Omega`

Explanation:

The current through the circuit, `I= 18/12 Amp= 3/2 Amp`

We know Power, `P = I^2R`, where R is the resistance.

Hence, `R = P/I^2 = (1 W)/(9/4 Amp^2) = 4/9 Omega`