# A charge of 18 C passes through a circuit every 12 s. If the circuit can generate 1 W of power, what is the circuit's resistance?

$\frac{4}{9} \Omega$
The current through the circuit, $I = \frac{18}{12} A m p = \frac{3}{2} A m p$
We know Power, $P = {I}^{2} R$, where R is the resistance.
Hence, $R = \frac{P}{I} ^ 2 = \frac{1 W}{\frac{9}{4} A m {p}^{2}} = \frac{4}{9} \Omega$