A charge of #18 C# passes through a circuit every #2 s#. If the circuit can generate #24 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-06-10T15:24:51

The resistance is #=0.296Omega#

The charge is related to the time and the current by the

#Q=It#^2=

The charge is #Q=18C#

The time is #t=2s#

The current is #I=Q/t=18/2=9A#

The power is

#P=UI#

But Ohm's Law states that

#U=RI#

So,

#P=RI^2#

Therefore,

#R=P/I^2=24/9^2=0.296Omega#