# A charge of 2 C is at (1,4 ) and a charge of -1 C is at (12 ,-5) . If both coordinates are in meters, what is the force between the charges?

Jun 27, 2016

Force F = $\frac{1}{4 \cdot \pi \cdot {\epsilon}_{0}} \cdot \frac{{q}_{1} \cdot {q}_{2}}{r} ^ 2$
Distance between charges r = sqrt((x_2-x_1)^2+(y_2-y_1)^2
Substituting the values we get answer as $- 89.02 \times {10}^{6} N$