A charge of #-2 C# is at #(-2 , 1 )# and a charge of #6 C# is at #(5, 3) #. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2017-12-23T07:45:56

The force is #=-2.0410^9N#

The distance between the charges is

#r=sqrt((5-(-2))^2+(3-1)^2)=sqrt(7^2+2^2)=sqrt53m#

The force between the charges is

#F=k(Q_1Q_2)/r^2#

The constant #k=9*10^9Nm^2/C^2#

The charge #Q_1=-2C#

The charge #Q_2=6C#

The force is

#F=910^9*(-2*6)/(53)=-2.0410^9N#

The minus sign indicates that the force is attractive