A charge of #-2 C# is at #(-2 , -7 )# and a charge of #6 C# is at #(5, 3) #. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2017-12-26T17:15:39

The force is #=-0.72*10.^9N#

The net force is

#F=k(q_1*q_2)/r^2#

The charge #q_1=-2C#

The charge #q_2=6C#

The distance #r=sqrt((5-(-2))^2+(3-(-7))^2)=sqrt(49+100)=sqrt149#

The Coulomb constant is #k=9*10^9Nm^2C^-2#

Therefore,

# F= 9*10^9 (((-2) *(6)) / (sqrt(149))^2) #

#=-0.72*10^9N#

The #-# sign indicates that the force is attractive.