A charge of #2 C# is at #(-3,7)# and a charge of #-1 C# is at #( 5, 2)#. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2017-12-23T14:03:21

The force is #=-2.02*10^8N#

The distance between the charges is

#r=sqrt((5-(-3))^2+(2-7)^2)=sqrt(8^2+5^2)=sqrt89m#

The force between the charges is

#F=k(Q_1Q_2)/r^2#

The constant #k=9*10^9Nm^2/C^2#

The charge #Q_1=2C#

The charge #Q_2=-1C#

The force is

#F=910^9*(2*-1)/(89)=-2.02*10^8N#

The minus sign indicates that the force is attractive