A charge of #2 C# is at #(5, 2)# and a charge of #-3 C# is at #( 7,-1) #. If both coordinates are in meters, what is the force between the charges?

1 Answer
Apr 10, 2016

Answer:

#F=-4,15*10^9" N"#

Explanation:

#"Force between two charges is given by Coulomb's law "#

#"given data:"#
#q_1=2C#
#q_2=-3C#
#P_1=(5,2)#
#P_2=(7,-1))#
#k=9*10^9 N*m^2*C^-2#
#F=?#

#"formula :"#

#F=k*(q_1*q_2)/d^2#

#"distance between two points is given by :"#
#d=sqrt((7-5)^2+(-1-2)^2)#

#d=sqrt(2^2+(-3)^2)#

#d=sqrt(4+9)=sqrt(13)#
#d^2=13" m"#

#F=9*10^9(2*(-3))/13#

#F=-54/13*10^9#

#F=-4,15*10^9" N"#