Question

A charge of `-2 C` is at `(-6, 4 )` and a charge of `3 C` is at `( -1, 5 )`. If both coordinates are in meters, what is the force between the charges?

Answer 1

The force is `=2.08*10^9N`

Explanation:

The force is

`vecF=k(q_1q_2)/r^2*vecr`

The charge `q_1=-2C`

The charge `q_2=3C`

The Coulomb's constant is `k=9*10^9Nm^2C^-2`

The distance between the `2` charges is

`r=sqrt((-1+6)^2+(5-4)^2)=sqrt26m`

Therefore,

The force is

`||vecF||=9*10^9*(2)*(3)/(26)=2.08*10^9N`

Since the chages are charged positive anf negative, the charges are attracted to one another with a force of `=2.0810^9N` and the direction is the line joining the `2` charges.