A charge of #-2 C# is at #(-6, 4 )# and a charge of #3 C# is at #( -1, 5 ) #. If both coordinates are in meters, what is the force between the charges?

1 Answer
Feb 3, 2018

Answer:

The force is #=2.08*10^9N#

Explanation:

The force is

#vecF=k(q_1q_2)/r^2*vecr#

The charge #q_1=-2C#

The charge #q_2=3C#

The Coulomb's constant is #k=9*10^9Nm^2C^-2#

The distance between the #2# charges is

#r=sqrt((-1+6)^2+(5-4)^2)=sqrt26m#

Therefore,

The force is

#||vecF||=9*10^9*(2)*(3)/(26)=2.08*10^9N#

Since the chages are charged positive anf negative, the charges are attracted to one another with a force of #=2.0810^9N# and the direction is the line joining the #2# charges.