A charge of #24 C# passes through a circuit every #12 s#. If the circuit can generate #8 W# of power, what is the circuit's resistance?

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Answer 1 · 2016-07-22T06:58:02

Resistance #R=2" "#Ohms

Given :

charge #q=24" "#coulomb
time #t=12" "#seconds
Power #P=8" "#watts

Solution:

Let #i# current in Ampere

#i=q/t=24/12=2" "#Amperes

#P=i^2 *R#

#8=(2)^2*R#

#8=4*R#

#R=8/4#

#R=2" "#Ohms

God bless....I hope the explanation is useful.