A charge of #24 C# passes through a circuit every #2 s#. If the circuit can generate #3 W# of power, what is the circuit's resistance?

Question

1155 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-23T05:23:01

The resistance is #=21mOmega#

The charge is related to the time and the current by the

#Q=It#

The charge is #Q=24C#

The time is #t=2s#

The current is #I=Q/t=24/2=12A#

The power is #=3W#

The power is

#P=UI#

But Ohm's Law states that

#U=RI#

So,

#P=RI^2#

Therefore,

#R=P/I^2=3/12^2=0.021Omega#