# A charge of 24 C passes through a circuit every 9 s. If the circuit can generate 32 W of power, what is the circuit's resistance?

Feb 7, 2016

$4.5 \Omega$

#### Explanation:

Electric current $I$ is the rate of flow of charge:

$I = \frac{Q}{t} = \frac{24}{9} = 2.66 \text{A}$

Power $P$ is given by:

$P = V \times I = 32 \text{W}$

So the voltage drop is given by:

$V = \frac{32}{I} = \frac{32}{2.66} = 12 \text{V}$

Using Ohm's Law:

$R = \frac{V}{I} = \frac{12}{2.66} = 4.5 \Omega$