A charge of #27 C# passes through a circuit every #3 s#. If the circuit can generate #63 W# of power, what is the circuit's resistance?

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Answer 1 · 2016-04-15T06:06:03

First step: #I=Q/t=27/3=9# #A#
Second step: #P=I^2R to R=P/I^2=63/9^2~~0.78# #Omega#