A charge of #35# #C# passes through a circuit every #5# #s#. If the circuit can generate #7# #W# of power, what is the circuit's resistance?

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Answer 1 · 2016-02-15T03:30:09

Convert the flow of charge into current, then use and rearrange #P=I^2R# to find that the resistance is #1/7# #Omega#.

Current is defined as the rate of flow of charge:

#I=Q/t=35/5=7# #A#

The power in a circuit can be expressed as:

#P=I^2R#

(Combining the equation #P=VI# with Ohm's Law, #V=IR# will yield this.)

Rearranging:

#R = P/I^2=7/7^2=1/7# #Omega#