A charge of #35 C# passes through a circuit every #5 s#. If the circuit can generate #21 W# of power, what is the circuit's resistance?
1 Answer
May 3, 2018
Explanation:
We first find the current produced in five seconds. Current is given by the equation,
#Q# is the charge in coulombs
#t# is the time in seconds
So, we get:
Now, power is related by the equation,
#I# is the current in amperes
#R# is the resistance in ohms
#P# is the power in watts
Rearranging for resistance, we get:
Plugging in our given values, we get: