A charge of #36 C# passes through a circuit every #6 s#. If the circuit can generate #6 W# of power, what is the circuit's resistance?
The circuit's resistance is around 0.17 Ohms.
The current, I, is equal to the charge passing through a point, every second.
I = dq / ds = 36C / 6 s = 6 C/s = 6 Amperes.
Now use, Power = P =
Enter known values for P and I.