A charge of #36 C# passes through a circuit every #6 s#. If the circuit can generate #72 W# of power, what is the circuit's resistance?

1 Answer
Dwight
Feb 8, 2017

The resistance of the circuit must be 2 ohms.

Explanation:

First, we determine the current that is flowing.

#I=q/t= (36 C)/(6 s) = 6 A

The rate of charge movement means a 6 amp current exists.

Next, use the relation #P=I^2R# to find the resistance

#72 W = (6 A)^2 xx R

#R= 72/36 = 2 ohms#

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