A charge of #36 C# passes through a circuit every #9 s#. If the circuit can generate #4 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-04-28T06:42:47

The resistance is #=0.25Omega#

We need Ohm's Law

#U=RI#

We apply the following equations

The power is #P=UI=RI^2#

and

The charge is #Q=It#

So,

#I=Q/t=36/9=4A#

And

The resistance is #R=P/I^2=4/4^2=0.25Omega#