# A charge of -5 C is at (1, 3 ) and a charge of 1 C is at (8,4 ) . If both coordinates are in meters, what is the force between the charges?

Mar 7, 2018

$3.6 \cdot {10}^{9} N$ or $3.6 G N$

#### Explanation:

You first want to use the coordinates to calculate a distance between the charges.
$d = \sqrt{{\left({x}_{2} - {x}_{1}\right)}^{2} + {\left({y}_{2} - {y}_{1}\right)}^{2}}$
The distance between the two charges is $5 \sqrt{2}$ meters
This will be your radius when calculating for the electric force. The formula for the electric force is
$F {e}^{-} = \frac{K {q}_{1} {q}_{2}}{r} ^ 2$
where $K = 9 \cdot {10}^{9}$ and the units for q is in coulombs and the r is in meters.
$F {e}^{-} =$($9 \cdot {10}^{9}$)($- 5$)(4)/${\left(5 \sqrt{2}\right)}^{2}$