# A charge of 5 C is at (-7, 1 ) and a charge of -3 C is at (8, -3) . If both coordinates are in meters, what is the force between the charges?

Sep 19, 2017

$5.6 \cdot {10}^{9} N$

#### Explanation:

Distance between (-7,1) & (8,-3) is 15.2 metres (source).
According to Coulomb's Law,
${F}_{e} = k | {q}_{1} \cdot {q}_{2} \frac{|}{r} ^ 2$
$\implies {F}_{e} = 9 \cdot {10}^{9} N {m}^{2} / {C}^{2} \cdot | - 5 C \cdot 3 C \frac{|}{15.52 {m}^{2}}$
$\implies {F}_{e} = 9 \cdot {10}^{9} N \frac{\cancel{{m}^{2}}}{\cancel{{c}^{2}}} \cdot \frac{15 \cancel{{C}^{2}}}{15.52 \cancel{{m}^{2}}}$
[After using my calculator 📟]😬
${F}_{e} = 5.6 \cdot {10}^{9} N$