# A charge of 54 C passes through a circuit every 6 s. If the circuit can generate 98 W of power, what is the circuit's resistance?

Jul 15, 2016

$R = 1.21 \Omega$

#### Explanation:

$I = \frac{\mathrm{dQ}}{\mathrm{dt}}$ will give momentary current, but as the current is constant

$I = \frac{\Delta Q}{\Delta t} = \frac{54 C}{6 s} = 9 A$

$P = {I}^{2} R \implies R = \frac{P}{I} ^ 2$

$R = \frac{98 W}{81 {A}^{2}} = 1.21 \Omega$