A charge of #-6 C# is at #(3, -1 )# and a charge of #-4 C# is at #( -3, 7 )#. If both coordinates are in meters, what is the force between the charges?

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Answer 1 · 2016-04-19T11:59:16

#F=216*10^7 N#

#"Force between the two point charges is given by formula"#
#F=k*(q_1*q_2)/r^2#
#r:"distance between (3,-1) and (-3,7")#

#F=k*((-6)*(-4))/((-3-3)^2+(7+1)^2)#

#F=k*(24)/(36+64)#

#F=k *24/100#

#F=9*10^9*24*10^-2#

#F=216*10^7 N#