# A charge of -6 C is at (3, -1 ) and a charge of -4 C is at ( -3, 7 ). If both coordinates are in meters, what is the force between the charges?

Apr 19, 2016

$F = 216 \cdot {10}^{7} N$

#### Explanation:

$\text{Force between the two point charges is given by formula}$
$F = k \cdot \frac{{q}_{1} \cdot {q}_{2}}{r} ^ 2$
r:"distance between (3,-1) and (-3,7")

$F = k \cdot \frac{\left(- 6\right) \cdot \left(- 4\right)}{{\left(- 3 - 3\right)}^{2} + {\left(7 + 1\right)}^{2}}$

$F = k \cdot \frac{24}{36 + 64}$

$F = k \cdot \frac{24}{100}$

$F = 9 \cdot {10}^{9} \cdot 24 \cdot {10}^{-} 2$

$F = 216 \cdot {10}^{7} N$