A charge of #6 C# passes through a circuit every #3 s#. If the circuit can generate #36 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-04-15T06:29:20

The resistance is #=9Omega#

The charge and the the current are related by the equation

#I=Q/t#

#I=6/3=2A#

We need the equation

#U=RI#

and

#P=UI=RI^2#

Therefore,

#R=P/I^2=36/2^2=9Omega#