A charge of #6 C# passes through a circuit every #3 s#. If the circuit can generate #72 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-06-03T05:51:48

The resistance is #=18Omega#

We apply the equation

#Q=It#

The charge is #Q=6C#

The time is #t=3s#

The current is #I=Q/t=6/3=2A#

The power is

#P=UI#

But according to Ohm's Law

#U=RI#

So,

#P=RI*I=RI^2#

So,

the resistance is #R=P/I^2#

#=72/(2)^2=18Omega#