A child has three plastic toys bearing the digits 3,3,5 respectively.How many 3-digit numbers can he make using them? Please solve this question without using the formula of permutations of objects not all different which is given by n!/P!×q!.
1 Answer
Oct 8, 2017
Numbers 335, 353, and 533 make a total of 3 numbers possible.
Explanation:
Without going to formulas, we can simply count the number of numbers:
335
353
533
There are 3 numbers possible.
