A chord with a length of #1 # runs from #pi/12 # to #pi/8 # radians on a circle. What is the area of the circle?

1 Answer

Area #=183.609" "#square units

Explanation:

From the data, an isosceles triangle can be formed with sides #1#, #r#, and #r#. The central angle #theta=pi/8-pi/12=pi/24#.

We can split this isosceles triangle into 2 right triangles with hypotenuse #r# and acute angle #1/2 theta=pi/48# and opposite to this acute angle #1/2 theta=pi/48# is side with length #1/2#.

We can now solve for #r#

#csc (pi/48)=r/(1/2)#

#r=7.64489#

and

Area#=pir^2=pi(7.64489)^2=183.609#

God bless....I hope the explanation is useful.