A chord with a length of #24 # runs from #pi/3 # to #pi/2 # radians on a circle. What is the area of the circle?

1 Answer
Nov 15, 2017

The area of the circle is #6753.36#

Explanation:

The chord forms the base of of an isosceles triangle where the legs are the radii

The internal angles of a triangle sum to #Pi#
The base angles of an isosceles triangle, where the apex is #a# radians can be calculated as
#(Pi - a)/2#

The angle at the apex of the triangle is #Pi/6#
Therefore, the equal angles are #(Pi - Pi/6)/2# or #5Pi/12#radians

The leg of an isosceles triangle can be calculated as half the base divided by the cosine of the base angle

Therefore, the radius (#r#) can now be calculated as
#r = 24/2 * 1/cos(5Pi/12) = 46.36444#

The area of a circle is given by #Pir^2#

The area of the circle is #Pi*46.36444*46.36444 = 6753.36#