A chord with a length of #3 # runs from #pi/8 # to #pi/6 # radians on a circle. What is the area of the circle?

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Answer 1 · 2016-06-04T22:32:02

It is #22.93#.

In a circle, the length of a chord is

#c=2rsin(theta/2)#

and so the radius is

#r=c/(2sin(theta/2)#

In our case theta is given by

#theta=pi/6-pi/8=pi/24#.

then

#r=3/(2sin(pi/48))\approx22.93#