# A circuit has two "6 Ω" resistors in parallel, given input current is 6A, What is the current at one resistor?

##### 1 Answer
Jun 11, 2018

$\text{3 A}$

#### Explanation:

In a parellel connection voltage remains same but current divides at the junction.

$\text{V = iR}$

"i" ∝ 1/"R" color(white)(...)[∵ "V = constant"]

For two resistors in parellel of resistances ${\text{R}}_{1}$ and ${\text{R}}_{2}$

${\text{i"_1 : "i"_2 = "R"_2 : "R}}_{1}$

From above

$\text{i"_1 = "R"_2/("R"_1 + "R"_2) × "i}$

$\text{i"_2 = "R"_1/("R"_1 + "R"_2) xx "i}$

Where $\text{i}$ is input current.

If resistances of both the resistors are same. Then,

$\frac{\text{i"_1 = "R"/("R + R") × "i" = "i}}{2}$

$\frac{\text{i"_2 = "R"/"R + R" × "i" = "i}}{2}$

So, we can conclude that if $\text{n}$ number of resistors of same resistances are connected in parellel then the current flowing through each resistor is

$\text{i"_"R" = "Total input current"/"Number of resistors connected in parellel" = "i"/"n}$

Answer to your question

$\text{i"_"R" = "6 A"/2 = "3 A}$