A closed beaker of circular cross section radius 4 cm is filled with Hg up to height 10 cm. Find the force exerted by the mercury on the bottom of the beaker?

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Answer 1 · 2017-08-09T15:32:02

67 N

The pressure at the bottom of the column is given by:

#sf(P=rhogh)#

#:.##sf(P=13534xx9.81xx0.1=13,276.85color(white)(x)"N/m"^2)#

The area of the bottom of the beaker is given by:

#sf(A=pir^2)#

#:.##sf(A=3.142xx0.04^2=0.005color(white)(x)m^2)#

#sf(P=F/A)#

#:.##sf(F=PxxA=13,276.85xx0.005=67color(white)(x)N)#