Question

A closed-ended tube is 2.8 m long. What is the wavelength of a first harmonic standing wave?

Answer 1

For a close ended tube,its open end bears antinode and the closed end bears node.

So,we can say `l=lambda/4` where,`l` is the length of the tube and `lambda` is the wavelength

So,for `1` st harmonic `lambda =4l=4*2.8=11.2m`