# A coin is tossed 4 times, what is the probability of NOT getting 2 heads?

Feb 21, 2016

Use the complement method ...

#### Explanation:

P(getting two heads) =(4!)/(2!xx2!)(1/2)^4=3/8
P(not getting 2 heads) $= 1 - \frac{3}{8} = \frac{5}{8}$