A company received a shipment of 2 types of parts. Three brass and 10 steel parts cost $48. A second shipment containing 7 brass and 4 steel parts cost $54. How do you solve system to find the cost of each part?

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A company received a shipment of 2 types of parts. Three brass and 10 steel parts cost $48. A second shipment containing 7 brass and 4 steel parts cost $54. How do you solve system to find the cost of each part?

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Answer 1 · 2015-10-23T00:44:19

I found:
brass: $$ 6$ $$6$
steel: $$ 3$ $$3$

Explanation:

Call the brass part $b$ $b$ and steel $s$ $s$ , so you get:
${\begin{matrix} 3 b + 10 s = 48 7 b + 4 s = 54 \end{matrix}$ ${(3b+10s=48),(7b+4s=54):}$
from the first equation:
$b = \frac{48 - 10 s}{3}$ $b=(48-10s)/3$ substitute into the second:
$7 \frac{48 - 10 s}{3} + 4 s = 54$ $7(48-10s)/3+4s=54$

$336 - 70 s + 12 s = 162$ $336-70s+12s=162$

$58 s = 174$ $58s=174$

$s = \frac{174}{58} = 3$ $s=174/58=3$
substitute back into: $b = \frac{48 - 10 s}{3}$ $b=(48-10s)/3$
$b = \frac{18}{3} = 6$ $b=18/3=6$

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A company received a shipment of 2 types of parts. Three brass and 10 steel parts cost $48. A second shipment containing 7 brass and 4 steel parts cost $54. How do you solve system to find the cost of each part?

1 Answer

Explanation:

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