Question

A company received a shipment of 2 types of parts. Three brass and 10 steel parts cost $48. A second shipment containing 7 brass and 4 steel parts cost $54. How do you solve system to find the cost of each part?

Answer 1

I found:
brass: `$6`
steel: `$3`

Explanation:

Call the brass part `b` and steel `s`, so you get:
`{(3b+10s=48),(7b+4s=54):}`
from the first equation:
`b=(48-10s)/3` substitute into the second:
`7(48-10s)/3+4s=54`

`336-70s+12s=162`

`58s=174`

`s=174/58=3`
substitute back into: `b=(48-10s)/3`
`b=18/3=6`