A compound contains 1.10 mol of K, 055 mol of Te, and 1.65 mol O. What is the simplest formula of this compound?

Dec 15, 2016

If we assume you meant $0.55 \cdot m o l$ $\text{tellurium}$, we get an $\text{empirical formula}$ of ${K}_{2} T e {O}_{3}$.

Explanation:

We divide thru by the SMALLEST molar quantity, that of tellurium, to get an empirical formula.

$\text{Moles of tellurium}$ $=$ $\frac{0.55 \cdot m o l}{0.55 \cdot m o l} = 1$

$\text{Moles of potassium}$ $=$ $\frac{1.10 \cdot m o l}{0.55 \cdot m o l} = 2$

$\text{Moles of oxygen}$ $=$ $\frac{1.65 \cdot m o l}{0.55 \cdot m o l} = 3$

And thus the empirical formula is ${K}_{2} T e {O}_{3}$.

All I have done is to divide thru by the SMALLEST MOLAR QUANTITY.