A compound with molecular formula C12H24 exhibits a 1H NMR spectrum with only one signal and a 13C NMR spectrum with two signals. What structure could be drawn for this compound?

1 Answer
anor277
Jan 22, 2018

I can suggest one candidate....#"octamethylcyclobutane.."#

Explanation:

astonchem.com

A formula of #C_12H_24# specifies one degree of unsaturation. And each degree of saturation specifies a DOUBLE BOND, or A RING. Now the spectroscopic data specify a high degree of symmetry (suggesting a ring...), and the #""^13C{""^1H}# #"NMR spectrum"# of the given molecule would give 2 signals....ONE due to the symmetric methyls, and ONE due to the ring carbons.

And the #""^1H# #"NMR spectrum"# would yield only the one signal, due to the chemically equivalent methyl groups. And these data fit with the question's specification....

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