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A compound with the empirical formula CH2 has a molar mass of 28 g/mol. What is the molecular formula for this compound?

1 Answer

Nov 28, 2015

The molecular formula is $C_{2} H_{4}$ $"C"_2"H"_4"$ .

Explanation:

Determine the empirical formula mass.

${CH}_{2} :$ $"CH"_2":$ $(1 \times 12 g/mol) + (2 \times 1 g/mol) = 14 g/mol$ $(1xx12"g/mol")+(2xx1"g/mol")="14 g/mol"$

Divide the molecular mass by the empirical formula mass.

$(28cancel"g/mol")/(14cancel"g/mol")=2$

Multiply the subscripts in the empirical formula times $2$ .

The molecular formula is $"C"_2"H"_4"$ .

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