A cone has a height of 12 cm12cm and its base has a radius of 7 cm7cm. If the cone is horizontally cut into two segments 3 cm3cm from the base, what would the surface area of the bottom segment be?

2 Answers
Apr 27, 2017

:.color(purple)(=374.19cm^2 to the nearest cm^2

Explanation:

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:.Pythagoras: c^2=12^2+7^2

:.c=L=sqrt(12^2+7^2)

:. c=Lcolor(purple)(=13.892cm

:.12/7=tan theta=1.714285714=59^@44’37”

:.color(purple)(S.A.=pirL#

:.S.A.=pi*7*13.892

:.S.A.=305.501

:.Total S.A.color(purple)(=305.501cm^2

:.Cot 59^@44’37”*9=5.25cm=radius of top part

:.Pythagoras: c^2=9^2+5.25^2

:.c=L=sqrt(9^2+5.25^2)

:. c=Lcolor(purple)(=10.419cm top part

:.S.A. top part=pi*r*L

S.A. top part:.pi*5.25*10.419

S.A. top part:.=171.844

S.A. top part:.color(purple)(=171.844cm^2

:.S.A. Bottom partcolor(purple)(=305.501-171.844=133.657cm^2

:.S.A. Bottom part=133.657+pi7^2+pi5.25^2=374.1851875cm^2

:.color(purple)(=374.19cm^2 to the nearest 2 decimal places cm^2

Apr 29, 2017

TSA = 374.19cm^2

Explanation:

We can use similar figures to answer parts of this question.

It is the same cone, so the angles are all equal and the sides are in the same ratio.
We can therefore compare the heights and the radii.

The Height of the larger cone H= 12cm

The height of the smaller cone: h = 12-3 = 9cm

The Curved Surface Area of the larger cone:

A = piRL

L is the slant height and is found from Pythagoras' Theorem:

L = sqrt(7^2 + 12^2) = sqrt193

A = 7pisqrt193

Use similar figures to find the radius of the smaller cone with a height of 9.

r/7 = 9/12

r = (9xx7)/12 = 5.25

Find the slant height:

l= sqrt(5.25^2 +9^2) = sqrt(108.5625)

The curved area is a = pirl

a = 5.25pisqrt108.5625

The curved surface area of the bottom part (fustrum) is the difference between the curved surfaces calculated above,

A = 7pisqrt193-5.25pisqrt108.5625

A= 133.66cm^2

The total surface area is made up of the curved surface area plus the areas of the upper and lower circles.

TSA = 133.66 + pi7^2 +pi5.25^2

TSA = 374.19cm^2