Question

A current of 250 amps is flowing through a copper wire with a resistance of `2.00 times 10^-4` ohms. What is the voltage?

Answer 1

The voltage is `=510^(-2)V`

Explanation:

We apply Ohm's Law

`U=RI`

The resistance is `R=2*10^(-4)Omega`

The current is `I=250A`

The voltage is

`U=RI=2*10^(-4)*250=500*10^(-4)=510^(-2)V`