# A cyclist increases his kinetic energy from 11 00 J to 5 200 J in 12 s. How can I calculate his power output during this time?

Apr 9, 2015

Power is the rate of change of output energy.

$P = \frac{\mathrm{dE}}{\mathrm{dt}}$ or $P = \frac{\Delta E}{\Delta t}$

Having said that, the change in energy

$\Delta E = {E}_{f} - {E}_{i} = 5200 J - 1100 J$

and your time interval $\Delta t = 12 s$.

Voila!