Question

A dilution of a 1.0 M NaOH solution was carried out as follows: 10.7 mL of the 1.0 M NaOH soution was diluted with distilled water to a total volume of 284 mL. Calculate the molarity (mol/L) of the diluted solution of NaOH?

Answer 1

Consider,

`M_1V_1 = M_2V_2`

This relates the volumes and molarities of two versions of the same solution—think of them as a ratio. Let's see it in action,

`1.0M * 0.0107L = M_2 * 0.284L`
`therefore M_2 approx 0.0377M`

This is reasonable, because since we have diluted the solution, with the moles of solute constant, it will have a lower molarity.

Answer 2

`[NaOH]=3.77xx10^-2*mol*L^-1`

Explanation:

`"Concentration"="Moles of solute"/"Volume of solution"`...

and so...

`(1.0*mol*L^-1xx10.7xx10^-3*L)/(284*mLxx10^-3*L*mL^-1)=3.77xx10^-2*mol*L^-1`