A drum rotates around its central axis at an angular velocity of 14.4 rad/s. If the drum then slows at a constant rate of 8.02 rad/s^2, (a) how much time does it take and (b) through what angle does it rotate in coming to rest?

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Answer 1 · 2015-12-03T07:29:26

#(a)#

#1.8"s"#

#(b)#

#12.92##" rad"#

I will use the equations of motion:

(a)

#v=u+at#

#:.0=14.4-8.02t#

#:.t=14.4/8.02=1.8"s"#

(b)

The angle through which it rotates is analogous to distance so we can use:

#s=ut+1/2at^2#

#:.s=14.4xx1.8-1/2xx8.02xx1.8^2#

#s=12.92# #"rad"#