# A fast food restaurant sold 24 burgers with cheese. If the ratio of burgers sold with cheese compared to without cheese was 3:2, how many burgers did they sell total?

Jun 29, 2018

See a solution process below:

#### Explanation:

We can write an relationship for this as:

$3 : 2 \to 24 : b$

Where $b$ is the number of burgers sold without cheese.

We can rewrite the relationship as an equation and solve for $b$:

$\frac{3}{2} = \frac{24}{b}$

$\frac{2}{3} = \frac{b}{24}$

$\textcolor{red}{24} \times \frac{2}{3} = \textcolor{red}{24} \times \frac{b}{24}$

$\frac{48}{3} = \cancel{\textcolor{red}{24}} \times \frac{b}{\textcolor{red}{\cancel{\textcolor{b l a c k}{24}}}}$

$16 = b$

$b = 16$

The restaurant would of sold $\textcolor{red}{16}$ burgers without cheese with the information provided in the problem.