A force 6i+3j+k displaces an object from A(0,3,2) to B(5,1,6) what is the work done?

1 Answer
Aug 9, 2018

Answer:

The work done is #=28J#

Explanation:

The work is the dot product of force and distance

The force is

#vecF=<6,3,1>#

The displacement is

#vec(AB)= <5-0, 1-3, 6-2> = <5, -2,4>#

The work is

#W=vecF.vec(AB) = <6,3,1> . <5, -2,4>#

#=(6xx5)+(3xx -2)+(1xx 4)#

#=30-6+4#

#=28J#